Brent,
In your diagram video of Game 4 after drawing the first sub-diagram with F in and H out you state: "All other options will have to have N in, and therefore T out."
The stimulus states that N and T are not both selected. This implies the following:
If N in then T out
If T in then N out
AND
Both T and N out.
Therefore, there is a third final option of BOTH T and N out.
Is this simply something they would test me on? If there is the possibility it seems to make the diagramming very difficult (i.e. I have to come up with even more diagrams in addition to the 6 already made). Do you have any advice?
